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Mathematics 19 Online
OpenStudy (anonymous):

dy=cx,for x the solution is x=?

OpenStudy (ash2326):

candance make the coefficient of x by someway?

OpenStudy (anonymous):

huh???? i dont understand what you are saying

OpenStudy (ash2326):

candance make the coefficient of x one by someway?

OpenStudy (radar):

(1/2)cx^2

OpenStudy (anonymous):

i am so confused... what does coefficient mean?

OpenStudy (ash2326):

is this calculus?

OpenStudy (anonymous):

no, its college algebra

OpenStudy (radar):

\[cx ^{2}\over 2\] that is the f(y) then dy/dx = cx

OpenStudy (ash2326):

then we have \[dy=cx\] divide both sides by c \[\frac{dy}{c}=x\]

OpenStudy (ash2326):

Radar here it's not the derivative of y. d, y, c and x are variables

OpenStudy (radar):

Yes, I believe you are correct, I was thinking the problem was y'

OpenStudy (radar):

@candance1109 ash2326 has the correct solution x=(dy)/c

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