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lim x- >infinity of : ((2x-5)^5) / (7x^2+2x-3)(x^3-6x) ??? common factor, or just distribute??
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no need to distribute...although that will work. Determine the highest degree in the numerator and the highest degree in the denominator.
Note that they are both 5
therefore the limit will be the coefficients of the leading terms.
2^5/7 or 32/7
you are only concerned with the leading term. leading term of the numerator is 32x^5 leading term of the denominator is 7x^5 Therefore the limit is the coefficient 32/7.
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ok let me try... Correct!!! thanks men!!>
sure.
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