Hi, I'm on ps1b, can't figure out why my code won't take the sum of my changing variable ln. Thanks!

prime=3.0
divisor=2.0
pcount=2.0
while pcount

Question

Hi, I'm on ps1b, can't figure out why my code won't take the sum of my changing variable ln.  Thanks!

prime=3.0
divisor=2.0
pcount=2.0
while pcount<1001.0:
    while (divisor<prime):
        if prime%divisor==0.0:
            prime=prime+2.0
            divisor=2
        elif prime%divisor!=0.0:
            divisor=divisor+1.0
    if divisor==prime:
        import math
        ln =  (math.log(prime,2.7182818284))
        print sum (ln)/prime
        prime=prime + 2
        divisor=2

anonymous · Answer

3rd line from the bottom, the sum (ln) part is messed up, the error says, 
 print sum (ln)/prime
TypeError: 'float' object is not iterable

anonymous · Answer

sum is designed to add the elements of a list.  Here ln is a scalar (a single value), not a list. Addition in Python is done using the + operator.

anonymous · Answer

if the variable ln is changing every time, how would you set that up? would it add the previous natural logarithims of the variable 'prime' to the already existing one?

anonymous · Answer

Here are a couple suggestions.   If you want to keep a running sum in a loop, begin by defining that variable outside of the loop.  It makes easier reading.  For example:
sum = 0
for x in range(1,10):
    sum = sum + x
print sum
At the end, 'sum' is the sum of the digits 1 through 9.

Only put things in the loop that need to happen on every pass through the loop.  For example, move 'import math' to the top of your program because it only needs to happen once.

anonymous · Answer

i didnt understand/realize how to use the for loop.  think I got it though, thanks!