Question

how do you write an equation in standard form for a line that passes throught the points -8, 4 and 4, -4?

Answer 1

Two-point form: y - y1 = [(y2-y1)/(x2-x1)](x - x1)

y -4 = [(-4-4)/(4 - -8)](x- -8)

y - 4 = [(-8)/(12)](x+8)

multiply both sides by 12

12y - 48 = -8x -64

simplifying further....

3y - 12 = -2x - 16

so it;'s,...

2x + 3y + 4 =0