Question

PROBLEM SOLVING USING SYSTEMS OF EQUATIONS
The length of a rectangle is 5cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the length and the width of the rectangle.

Answer 1

L=5+2w
2L+2w=34
substitute for L

Answer 2

let L = length of rectangle
W = width of rectangle
P = perimeter

L = 5 + 2w
2L + 2W = 34

L - 2W = 5
2L +2W = 34

3L = 39
L = 13
W = 4

Answer 3

how would you do that with x and y?

Answer 4

just use x and y instead of L and W

Answer 5

thankyou!