PROBLEM SOLVING USING SYSTEMS OF EQUATIONS
The length of a rectangle is 5cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the length and the width of the rectangle.

Question

PROBLEM SOLVING USING SYSTEMS OF EQUATIONS
The length of a rectangle is 5cm more than twice the width.  The perimeter of the rectangle is 34 cm. Find the length and the width of the rectangle.

cathyangs · Answer

L=5+2w
2L+2w=34
substitute for L

lgbasallote · Answer

let L = length of rectangle
W = width of rectangle
P = perimeter

L = 5 + 2w
2L + 2W = 34

L - 2W = 5
2L +2W = 34

3L = 39
L = 13
W = 4

anonymous · Answer

how would you do that with x and y?

cathyangs · Answer

just use x and y instead of L and W

anonymous · Answer

thankyou!