Question

f(x)= (6x)−1/2 + 5
f ' (x) =?

Answer 1

6x^-1/2

Answer 2

(-1/2)(6)(x^(-3/2)

Answer 3

-1/2(6x^-3/2)

-1/[2 sqrt of (6x)^3]

Answer 4

well f'(x) = -3x^-3/2

\[f '(x) = -3/\sqrt{x^3}\]

Answer 5

i've already tried -3x^-3/2 and -3/sqrt3 but i have not tried -1/2 sqrt of 6x^3

Answer 6

nahhh. that was wrong :)) 6 should be in the numerator

Answer 7

somehow the answer is -1/2x*sqrt6x..... dont know how

Answer 8

just look at my solution....

Answer 9

idk how though

Answer 10

you have -1/2 * 6 = -3 x^(-3/2) = 1/x^3/2 so its 3 * 1/x^3/2