Can someone please help me with this? What is the volume of the solid generated by revolving the region bounded by the given lines and curves about the x-axis?
y= sq root(3x) y=3, x=0

Question

Can someone please help me with this? What is the volume of the solid generated by revolving the region bounded by the given lines and curves about the x-axis? 
y= sq root(3x) y=3, x=0

anonymous · Answer

maybe x=3 not y=3

anonymous · Answer

no it is y=3

anonymous · Answer

$$\int\limits_{0}^{3}3*\pi*xdx=1.5x^2*\pi|=1.5*9*\pi$$ i dont know how to solve if there y=3

dumbcow · Answer

|dw:1328690052250:dw|

$$V = \pi \int\limits_{0}^{3}R^{2} -r^{2} dx$$
$$V = \pi \int\limits_{0}^{3}3^{2} -(\sqrt{3x})^{2} dx$$