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Mathematics 17 Online
OpenStudy (anonymous):

the exact value of this logarithm? ln√e

OpenStudy (anonymous):

\[\frac{1}{2}\]

OpenStudy (anonymous):

how :S

OpenStudy (anonymous):

since \[\ln(\sqrt{e})=\ln(e^{\frac{1}{2}}\] w

OpenStudy (anonymous):

typo i mean \[\ln(\sqrt{e})=\ln(e^{\frac{1}{2}})\]

OpenStudy (anonymous):

when you have logs good to write in exponential notation

OpenStudy (anonymous):

\[\ln(x)=y\iff e^y=x\] so so you are solving \[e^y=e^{\frac{1}{2}}\]

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