Question

help w/ quadratic equation: -0.01x^2+50x-62100=0

Answer 1

a=-0.01
b=50
c=62100

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Answer 2

since there is a +or- you will get 2 answers for x

Answer 3

i know but i need help solving it

Answer 4

-0.01x^2+50x-62100=0
x^2-5000x+6210000=0

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 5

Zed can help you with that, but it's literally just plugging in the values for a b c into the equation

Answer 6

Here a=1, b=-5000 and c=6210000

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]\[=\frac{5000 \pm \sqrt{(-5000)^2-4*1*6210000}}{2*1}\]\[=\frac{5000 \pm \sqrt{25000000-24840000}}{2}\]\[=\frac{5000 \pm \sqrt{160000}}{2}\]\[=\frac{5000 \pm 400}{2}\]\[=2500 \pm 200\]

So x=2700 or x=2300