Ask
your own question, for FREE!
Mathematics
31 Online
OpenStudy (anonymous):
An unmarked police car traveling a constant 85km/hr is passed by a speeder traveling 140km/hr. About 3.00s after the speeder passes, the police officer steps on the accelerator, if the police car's acceleration is 1.80m/s^2 , how much time passes before the police car ovetakes the speeder after the speeder passes?(assumed moving at constant speed)
Still Need Help?
Join the QuestionCove community and study together with friends!
OpenStudy (anonymous):
This is a physics question involving kinematic equations. So far I've set up my problem as such: t = 3.00s, v-speeder140km/h, v-p: 85km/h. a-p: 1.80m/s^2. V stands for velocity of speeder and police car and a stands for acceleration.
OpenStudy (anonymous):
I'm thinking that I would need to use this kinematics equation: d= vt+1/2at^2
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
persephone:
The emergency notification echoed in the theater as everyone reached for their phones to discover what was interrupting their movie.
4 hours ago
4 Replies
0 Medals
Juss1Jordan:
The way that this guy treats me make me feel wanted in this world not gonna say his name or @ cs the boy is mines .
5 hours ago
8 Replies
1 Medal
velmalovesshaggy145:
Isnu00b4t this the opening melody to mood by 24kgoldn feat iann dior? https://voca.
49 minutes ago
9 Replies
2 Medals