Question

converge or diverge?
An = (1-3/n)^2n

Answer 1

Most likely Converge.

Answer 2

Can you prove it? Im stuck at lny = ln(1-3n)/(1/2n)

Answer 3

\[\left(1-\frac{3}{n}\right)^{2n}\]

after taking the natural log you will have

\[\frac{\ln\left(1-\frac{3}{n}\right)}{\frac{1}{2n}}\]

now use L'Hospitals rule