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determine if the following function is even p(x)=2x^4-6x+1
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hint, one of the exponents is NOT even
your teacher wants you to write \[p(-x)=(-x)^2-6\times (-x)+1=x^2+6x+1\] and since this is NOT \[-p(x)\] the answer is no
for a function to be even the condition is f(-x) = f(x). for a function to be odd the condition is f(-x) = -f(x) if neither condition is satisfied, the function is neither odd nor even
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