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A diameter of a circle has endpoints at (4, 6) and the origin. Which point is also on the circle? A. (–1, 2) B. (6, 3) C. (5, 0) D. (–1, 1) E. NOTA Please explain.
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find the midpoint x = (4 + 0)/2 y = (6 + 0)/2 that will give the centre
then the equation is (x - h)^2 + (y-k)^2 = r^2 in this case r^2 = 52 (h, k) is the centre... sub in each point... to test
answer is D (-1,1) please can you show more steps
I didn't get it
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