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A druggist wants to reduce a 20-ounce quantity of a 7% solution of iodine to a 4% solution by adding pure alcohol. How much alcohol must he add to accomplish this?
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Heeeellllppp !
LOL i am getting a negative answer ~.~
lol ahaha, well that kinda sucks =/
whats the answer in any case?
iodine_before = iodine_after to find the amount of iodine, multiply volume by concentration x is amount of alcohol added --> 20(.07) = (20+x)(.04) 1.4 = .8 +.04x .6 = .04x 15 = x
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