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OpenStudy (anonymous):
Heres another one :D An alloy of tin and copper contains 16% tin. How much tin (to the nearest tenth) must be added to make 820 pounds of alloy that is 18% tin?
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OpenStudy (dumbcow):
Alloy Tin Before x .16x After 820 820*.18 =147.6 Since we are adding only tin, the difference in weight should be the same 820-x = 147.6 - .16x .84x = 672.4 x = 800.48 difference = 820 - 800.48 = 19.52
OpenStudy (ar43r):
nice solution!
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