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Physics 14 Online
OpenStudy (aravindg):

pls explain hw we goot the eqns like e^2h and all in this fig.the fig shows a ball bouncing and eventually coming to rest (note e is coefficient of restitution

OpenStudy (anonymous):

The coefficient of restitution for an object bouncing off of a stationary object is defined as\[C_R =e = {v \over u}\] where \(v\) is the velocity after impact and \(u\) is the velocity before impact. From the equations of projectile motion, we can express this as\[C_R = e = \sqrt{ h \over H}\]where \(h\) is the bounce height and \(H\) is the drop height.

OpenStudy (aravindg):

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