Question

Find equation of a tangent line to the graph of f(theta)=tan(theta) at point(pi/4, 1)

Answer 1

f'(x) = 1/cos^2
at x = pi/4
cos(pi/4) = sqrt2/2

f'(pi/4) = 1/(1/2) = 2 --> slope
y = mx+b
1 = 2(pi/4) + b
b = 1-pi/2

--> y = 2x +(1-pi/2)

Answer 2

thank you

Answer 3

thank you

Answer 4

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