Question

if they give me amplitude:3 phase shift: -1/6 and period: 5pi whats the equation for sine
please help!

Answer 1

\[Asin(\omega t+\phi)\]
Also, angular frequency is
\[\omega=2\pi f \]
Frequency in Hertz is
\[ f=\frac{1}{T}\]
where T is the period.
so:
\[A= 3, f=\frac{1}{5 \pi}, \omega=2 \pi f= \frac{2}{5},\phi=-\frac{1}{6}\]
\[3\sin(\frac{2}{5}t-\frac{1}{6})\]