Ugh, algebra! Help please, if you can. :( You are serving bratwurst and hamburgers at a picnic. You want at least 3 brats or hamburgers for each of your 50 guests. Brats cost $1.25 each, and hamburgers cost $0.95 each.Your budget is $200. Write a system of inequalities that represents this solution. Thank you! TT_TT
alright well let's try work this out together.
let B = bratwurst let H = hambuggas
50 guests in total
cost of B = 1.25 cost of H = 0.95
total spendable money is 200
the sum of B+H for each guest is 3
Is it B+ H> or equal to 150?
sorry B+H>=3
or, maybe this: 1.25B+0.95H>=(50)(3)
or wait no, sorry, got ahead of myself disregard last equation.
B+H>=150.. like you said, but then you need another equation
1.25B+0.95H<=200
No problem. Thank you for helping me. I THINK, is it...1.25B+.95H=200?
maybe.. i dunno.
yes and the second equation should depend on the first. so B and H will be the number of brats and burgs
so i would include the <= just so you are implying that since 200 is a budget, it doesn't mean you have to use ever penny of it
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