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Mathematics 13 Online
OpenStudy (laddiusmaximus):

using the squeeze theorem solve lim x-->0 x^2 cos 1/x

OpenStudy (anonymous):

0

OpenStudy (laddiusmaximus):

walk me through it.

OpenStudy (zarkon):

\[-x^2\le x^2 cos(1/x)\le x^2\]

OpenStudy (laddiusmaximus):

why x^2?

OpenStudy (anonymous):

if x^2 has lim and -x^2 has lim and they are equal then x^2cos(1/x) has the same lim exatct zero

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