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Mathematics 20 Online
OpenStudy (laddiusmaximus):

using squeeze theorem, solve limx-->0 x sin 1/x^2

OpenStudy (anonymous):

It should be Since 1 > sin(1/x^2) > -1, hence, lim x-> 0 x.sin(1/x^2) = 0, Sorry, i am not sure how to write it mathematically.

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