A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 12 square feet. Find the lengths of the sides of the poster and the sign

Question

A square poster has sides measuring 2 feet less than the sides of a square sign.  If the difference between their areas is 12 square feet.  Find the lengths of the sides of the poster and the sign

anonymous · Answer

It's easy!
what is the formula for a square?

anonymous · Answer

I won't be able to help you if you will just be silent!

anonymous · Answer

I got 16ft for the sign and 4 ft for the poster does that seem correct to you?

anonymous · Answer

does it match yours>?

anonymous · Answer

Well, let's see!
a ( is a poster ) and b ( sign)

Area = a^2
Area = b^2

b^2 - a^2 = 12

if a = b- 2 we just plug it in our formula!

b^2 - (b-2)^2 = 12
b^2 - b^2 + 4b - 4 = 12
4b - 4 = 12
4b = 16
b = 4

Area for b = 16
Area for a = 4

You are correct :)

anonymous · Answer

yay thanks for checking with me hugs