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After t hours, Liza's distance from home, in miles, is given by D(t) = 138 + 40(t-3) what is the practical interpretation of the constants 3 and 138?
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i'm not sure if this is right but here's what i think and i'll let someone confirm or provide the correct answer... from y=mx+c I believe that 138 is the distance she was away from home after 3 seconds.
after t "hours"
thought she was that far (138) at the beginning.
When t=0
no IsTim - sasogeek is right (except for the units of time).
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40*3 would change the distance when t=0
Sigh. IsTim is wrong again.
but IsTim has learnt now :D
well put saso :D
Thanks for your help guys
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anytime ;)
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