Question

x^3+27+0 please factor with steps

Answer 1

27+0? or is there another x?

Answer 2

no his question is right

Answer 3

(x+3)(x^2 -3x +9)

Answer 4

+0 is kinda weird

Answer 5

math textbooks are kinda weird. lol

Answer 6

i meant =0 my bad

Answer 7

(x+3)(x^2 -3x +9) = 0

x + 3 = 0

x = -3

x^2 -3x +9 = 0

Answer 8

\[x^3+27=0\]\[\mathsf { We \ Can \ write \ it \ as \ (x)^3 + (3)^3 =0 } \]\[\mathsf {Now \ use \ the \ formula \ (x)^3 + (y)^3= (x+y)(x^2-xy+y^2)} \]
\[\mathsf {(x+3)(x^2 -3x +9) = 0}\]\[\mathsf {x + 3 = 0 \ and \ x^2-3x+9=0 }\]\[\mathsf {x = -3} \] \[ \mathsf { x^2-3x+9=0 }\]