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Mathematics 14 Online
OpenStudy (anonymous):

solve x^2+2x-15=0

hero (hero):

x^2+2x-15= 0 x^2+5x-3x-15 =0 x(x+5)-3(x+5) = 0 (x+5)(x-3) = 0 x = -5 x = 3

OpenStudy (anonymous):

thanks!

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