Can someone help with finding the velocity of this?? I don't understand.

Question

beth12345 · Answer

It's question 8... http://xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s10_qp_11.pdf

anonymous · Answer

Slope of tangent of velocity-time graph gives accelaration.
V at any instant 't' = dv/dt at 't'
Hope you know what to do next.

beth12345 · Answer

um, I don't really know, do you know what the answer is?

anonymous · Answer

Hi
first you ought find V equation & differentiate from it  proportion t to reaching  acceleration equation in general V is$$V=bt ^{2}+ct+V _{0}$$
we know v0=4 if you differentiate from V yields$$a=2bt+c$$
in t=0 a=0 so reaches c=0 now V equation is$$V=bt ^{2}+4$$
from graph we can find b so b=.222222222222222222222
finally V is:$$0.22222222t ^{2}+4$$
differentiate  proportion t from above & find acceleration on t=3 i find 1.3