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okay guys Im stuck and i don't know what to do after this step. here is the problem: 12b^2-29b+15 me: 3(b^2+20b)(9b+5) It has to be factored out by grouping why do I feel it is not complete?
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Call ghost busters
Oh mrs happy you got jokes I like a jokester
are you a smart jokester?
\[12b^2-29b+15\]\[(4b-3)(3b-5)\]This is what you should have done. I'm not sure how you got your answer. This one shouldn't be factored by grouping as it only has 3 terms.
thanks X I appreciate your input.
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no prob
If you'll notice, if you re-simplify your answer, you won't get the original expression. This is one way to check yourself.
Thanks X I am going to do that next time to be sure:)
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