Question

a car is traveling in a straight line and decelerating at a constant rate. after 3.2 seconds it has traveled 88m and slowed to a speed of 27 m/s what is the initial speed i got 52 m/s

Answer 1

\[\Delta X=\frac{1}{2}(Vi+Vf)t\]\[88m = \frac{1}{2}({Vi+27 m/s})3.2s\]
Solving for Vi you get 28 m/s