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at what point is this function continuous, y=lx-1l+sin x, the answer is all X's, is this because of the abslt value? (l_l this means abslt value)
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t would be continuous without the absolute value as well it is only going to be discontinuous if it is either a 'step function', if the formula allows for division by zero, or a negative square root. none of that is the case here
polynomials are continuous functions(except of course you have a fraction) and trigonometric functions(except tan and cotan) are also continuous so their sum is also continuous
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