Question

Write the equations of the asymptotes and label them on the coordinate plane for the function g(x)=[1/(x-1)]+2, please.

Answer 1

the vertical asymptote lies at x = 1. If x= 1 then the denominator is will be zero and undefined. The vertical asymptote is y = 2... and x gets very large then 1/(x-1) will get very small and tend to zero.... so the function will get close to the constant value of 2