Question

Dont Understandd . ..
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2.

Answer 1

it starts out :Y= x^2+4x-

Answer 2

y=a(x-h)^2+k
(h,k) is the vertex and for x and y we can use one of the x intercepts. Let's choose (2,0)
0=a(2+2)^2-16
0=16a-16
a=1

Answer 3

y=1(x+2)^2-16 is the required equation. If you want it in a different form, it can be rearranged.

Answer 4

y=x^2+4x+4-16
y=x^2+4x-12

Answer 5

That makes sense. Thank You .