Question

determine the value of the constant k for which the equation has equal root (that is only oe distinct root)
x^2+2(k+1)x+k^2=0

Answer 1

Is there a certain formula that goes with the constant k

Answer 2

use the descriminant.... b^2 - 4ac... equal roots the descriminant = 0

so (k+1)^2 - 4 x 1 x k^2 = 0.

expand and simplify... you'll then have a quadratic that needs to be solved..

something like 1 + 2k -3k^2 = 0

Answer 3

thanks for you help tonight.