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Mathematics 9 Online
OpenStudy (anonymous):

integrate 2x cosh x dx, upper limit = 1, lower limit = 0.

OpenStudy (anonymous):

\[\int\limits_{0}^{1} 2x \cosh 2x dx\]

OpenStudy (anonymous):

Is it cosh x or cosh 2x?

OpenStudy (turingtest):

just use integration by parts

OpenStudy (anonymous):

For the first one it would be 2 - 2 / e.

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