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OpenStudy (anonymous):
What are the solutions for x in the proportion 5x-6 (over) x = 2x (over)2
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OpenStudy (king):
x=3,2
OpenStudy (anonymous):
(5x-6)/x = 2x/2 => (5x - 6)/x = x \[x ^{2} - 5x + 6 = 0 => x= 2 or x = 3\]
OpenStudy (king):
use quad. equation formula
OpenStudy (anonymous):
thank you
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