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If i have 3 over the (sqrt) 3 would it just be 3 since 3 is prime?
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\[(3\sqrt{3} )/3\]
3/(sqrt)3
\[3 \over \sqrt{3}\]
yes
Simplify by rationalizing the denomintor
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i did but im not sure if my answer is correct
is it 3
\[{{3}\over{\sqrt{3}}}= {{\sqrt{3}\times \sqrt{3}}\over{\sqrt{3}}}=\sqrt{3}\]
ohh okay thanks
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