Question

(sqrt)486 - (sqrt)24 + (sqrt) 6

Answer 1

factor each integer, then pull any perfect squares outside of the radical

Answer 2

for example
\[486=2\times 3^5\] so
\[\sqrt{486}=3^2\sqrt{2\times 3}=9\sqrt{6}\] each term will have a
\[\sqrt{6}\] in it, then combine like terms

Answer 3

is it 2(sqrt)6 or 8(sqrt)6