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find u and v where sinu=2sinv and cosu+2cosv=2
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try squaring the first one and then using the rule:\[\sin^2(x)=1-\cos^2(x)\]
sure, just managed it with cos2x=1-sin^2x but it felt a bit over the top; thought there might be a better way
I think thats the right approach.
coool
thanks
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yw
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