Question

5^(x+2)-25^(x+0.5)=2(5^(x+1)), solve the equation leaving answer in 2 decimal places. I used substitution and arrive at the answer of a=0 & a=3, but do not know how to get x.

Answer 1

where did the a come from?

Answer 2

i get x = 0.68

Answer 3

By rearranging and expanding terms:
\[\rightarrow \frac{25*5^{x} -5*5^{x}*5^{x}}{5*5^{x}} = 2\]
After factoring out a 5*5^x
\[\rightarrow 5-5^{x} = 2\]
\[5^{x} = 3\]