Question

find the perimeter of the right triangle given the length of one leg and the area
a=6m
area= 24m squared

Answer 1

area = 1/2*base*height
base and height are the legs of triangle
24 = 1/2*6*b
24 = 3b
8 = b

Then use pythagorean theorem to get c (hypotenuse)
c^2 = 6^2 +8^2
c^2 = 100
c = 10

perimeter = 6+8+10