Question

One number is 1 less than a second number. Twice the second number is 20 less than 4 times the first. Find the smaller of two numbers.

Answer 1

Let 1st number be A, 2nd num be B

A = B-1
2B = 4A -20

--> 2B = 4(B-1) -20
2B = 4B -24
B = 12

--> A = 12-1 = 11
smaller num is 11

Answer 2

the 2 numbers are x and (x-1) then 2(x-1) = 4x -20

Answer 3

2x - 2 = 4x - 20
18 = 2x

x = 9

then x-1 = 8

Answer 4

Thanks