An unfingered guitar string is 0.70 m long and is tuned to play E above middle C (330 Hz). How far from the end of this string must the finger be placed to play B flat above middle C (466 Hz)?

Question

mani_jha · Answer

$$330=piv/L$$
L=0.7. find v.
$$466=\pi v/l$$
put v and find l.

anonymous · Answer

$$f = nv \div2l$$ n is the number of nodes, so 
$$330 = v \div2l$$ since n = 1
$$466 = nv \div2l$$
l/n gives the answer

mani_jha · Answer

Oh yeah, sorry i forgot to convert the angular frequency to linear frequency. Thanks for correcting lucifur