Question

how do I solve this?
16x^2-72x-40=0

Answer 1

quadratically

Answer 2

i am having problems with it I know it is quadratic

Answer 3

problems in the method you chose? or in dealing with the quadratic formula?

Answer 4

we can factor out a 4

4(4x^2 -18x - 10) = 0 and ignore the 4

Answer 5

10*4 = 40; factors of 40 that subtract to 18 if its integerable

Answer 6

1 40
2 20 ... that does it

Answer 7

(x-20/4)(x+2/4)

(x-5)(x+1/2)

4 (x-5) (2x+1) = 0

Answer 8

im missing something i think

Answer 9

no that is the answer -1/2 and 5

Answer 10

ya!!

Answer 11

i see what i did, I forgot to factor out another 2 along the way; but yeah, same "answers"

Answer 12

2x^3-11x^2+15x=0

Answer 13

how do i do this one

Answer 14

there is no gcf

Answer 15

there is a gcf; its "x"

Answer 16

x (2x^2 -11x + 15) = 0 ; well, when x=0 for starters

Answer 17

2*15 = 30

factors of 30 that add up to 11 are 6 and 5

(x-6/2) (x-5/2)

x = 3 and x=-5/2 should zero it out then as well