Give the best method for solving 2y^2+8y=0 a.factoring b.property of sqaure roots of equal numbers c.completing the square d. quadratic formula
there is no "best method"
welll its in my book and its multiple choice and those are the answers so i have to pick one
the "best method" is the one that gets a solution. and since b is the only thing i dont recognize id try to avoid that one
so quadratic formula
factoring is the easiest..
I'd say factoring...
by factoring: 2y^2 + 8y = 0 2y (y + 4) = 0 y = 0, -4 .......................... by CTS 2y^2 + 8y = 0 y^2 + 4y = 0 y^2 + 4y +4 = 4 (y+2)^2 = 4 y+2 = +- sqrt(4) y = -2 +- 2 ; y=0, -4 ------------------------ quad form 2y^2 + 8y = 0 -8 +- sqrt(8^2-4(2)(0)) -------------------- 2(2) -8 +- 8 ------- ; y = 0, -4 4
there is no "best" method of solving this
k thanks youn tried but you stilll arent getting what im asking but whatever
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