Question

How many square metres of canvas is required for a conical tent whose height is 3.5m and radius of whose base is 12m? (Use pie= 22/7)

Answer 1

Assuming you don't want to cover the base in canvas, you'd subtract the area of the circlular base from the total surface area of the cone

Answer 2

Surface area of a cone is given by pi(r^2) + pi (r)(l)

22/7 * 12^2 + 22/7 (12)(3.5)
surface area is 207 squaremeters.

if u just want the top part then its just this pi (r)(l)

Answer 3

C = 2pir; = 24pi

rn (new radius) = sqrt(3.5^2+12^2) = sqrt(...hmmm); sqrt(156.25)

35
35
925
150
150
----
12.25
144
------
156.25 ?

C = t rn
area = t rn^2/ 2

area = C rn^2/2 rn = C rn/2

maybe :)

Answer 4

let me dbl chk that :)

part of the circumference of flattened cone with a slit is the circumference of the cone base:

24 pi

radius of flattened cone is slant height of cone; sqrt((3.5)^2 + 12^2) = 12.5

area of a sector: angle*r^2 / 2

arclength (C) of a sector is: angle * r

angle = C/r

C r^2
----- = Cr / 2
2 r

12.5 * 24pi / 2 = 12.5 * 12 * 22/7 = abt 471 ; so i might be off somewhere :)

Answer 5

yeah, so that should be good :)

Answer 6

it is 471..