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Mathematics 16 Online
OpenStudy (anonymous):

Am I right on this one, did I leave anything out, or not. Solve the following equation in the real # system. 2x^3-x^2+2x-1=0 a=2,b=-2, c=-1 x^2(2x-1)+(2x+1)=0 (x^2+1)(2x-1)=0 x=1/2, i, -i

OpenStudy (mertsj):

Good job!! You nailed it!

OpenStudy (anonymous):

good ty

OpenStudy (mertsj):

yw

OpenStudy (anonymous):

Very good. But you should note that \(i\) and \(-i\) are not real solutions.

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