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OpenStudy (anonymous):
b+a'bd+ab'c+ac'd+ad'=x b(1+a'd) + a(b'c +c'd+d') = b+a(b'c+c'd+d') =b+(ab')=b+a how do you cancel the c+c'd+d?
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OpenStudy (anonymous):
http://mathworld.wolfram.com/BooleanAlgebra.html idk anything about it but this seems informative?
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