Question

Find the derivative of f(x)= 4x / (x+3)^3.
I just need help rewriting the equation

Answer 1

[4(x+3)^3 - 12x(x+3)^2]/(x+3)^6
{4(x+3)[(x+3)^2 - 3x(x+3)]}/ (x+3)^6
{4[(x+3)^2 - 3x(x+3)]}/(x+3)^5
{4(x^2 + 6x + 9 - 3x^2 - 9x}/(x+3)^5

[4(4x^2 -3x + 9)]/(x+3)^5

(16x^2 - 12x + 36)/(x+3)^5