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Find the force of gravity between two 74.0kg physics students that are sitting 85.0cm apart.
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F=G(m_1)(m_2)r^-2 We have m_1, m_2, and r. (Although I'd convert the cm to m.) We also know G, as it's a constant.
I know how to do it, i just wanted to see if you got 5.1x10^-7 for your answer
\[\frac{6.67x10^{11}*74.0kg^2}{(0.85m)^2} \approx 5.055x10^{-7}\]so yes :)
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