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is x+1/x^2-1 equivalent to x/x-1
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no
\[\frac{x+1}{(x+1)(x-1)}=\frac{1}{x-1}\] so long as x is not -1
is 2x+4/4 equivalent to 2
two equations are equivalent when they have the same solution set (if i remember correctly)
I would have said, thanks, but what ever
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no it isn't
\[\frac{2x+4}{4}=\frac{2(x+2)}{4}=\frac{x+2}{2}\]
is x^2y^3z/xy^2 equivanent to xz/y^-1
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