Question

Find the magnitude and directional angle for the following vector. <-4,4sqrt3>

Answer 1

then it would have angle using trig functions, for example,
\[\tan^{-1} \theta = 4\sqrt{3} \div -4\]

Then your magnitude would be determined by
\[|v| = \sqrt{ x ^{2} + y ^{2}} \rightarrow |v| =\sqrt{ 4^2 + (4\sqrt{3})^2}\]